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If the tangent at (1, 7) to the curve x^{2}=y-6 touches the circle x^{2}+y^{2}+16x+12y+c=0 then the value of
c is :

  • Option 1)

    95

  • Option 2)

    195

  • Option 3)

    185

  • Option 4)

    85

 

Answers (2)

best_answer

Tangent at a point T = 0

xx_{1}= \frac{y+y_{1}}{2}-6

1x= \frac{y+7}{2}-6

2x= y+7-12

2x= y-5

2x- y+5=0

perpendicular distance = r

\frac{-16+6+5}{\sqrt5}= \sqrt(8^{2}+6^{2}-c)

\sqrt5 = \sqrt(100-c)

c= 95

 

Equation of tangent -

yy_{1}= 2a\left ( x+x_{1} \right )

 

- wherein

Tangent at  P\left ( x,y_{1} \right )on  y^{2}=4ax

 

 

 

 

 

 

 

 


Option 1)

95

Option 2)

195

Option 3)

185

Option 4)

85

Posted by

gaurav

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