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A plane polarized light is incident on a polariser with its pass axis making angle θ with x-axis, as shown in the figure. At four different values of θ, θ= $8^{\circ}$ , $38^{\circ}$ , $188^{\circ}$ and $218^{\circ}$ , the observed intensities are same. What is the angle between the direction of polarization and x-axis ?

Option 1)
$98^{\circ}$

Option 2)
$128^{\circ}$

Option 3)
$203^{\circ}$

Option 4)
$45^{\circ}$

Answers (1)

best_answer

As we learnt

Malus Law -

$I= I_{0}\cdot \cos ^{2}\theta$

$\theta =$ angle made by E vector with transmission axis.

- wherein

$I=$ Intensity of transmitted light after polarisation .

$I_{0}=$ Intensity of incident light.

I is same for $\theta=8^{\circ},38^{\circ},188^{\circ},218^{\circ}$

Only possible value is $203^{\circ}$

As

$203^{\circ}-8^{\circ}=195^{\circ}\: \: (180^{\circ}+150^{\circ})$

$203^{\circ}-38^{\circ}=165^{\circ}\: \: (180^{\circ}-150^{\circ})$

$203^{\circ}-188^{\circ}=15^{\circ}$

$203^{\circ}-218^{\circ}=-15^{\circ}$

Option 1)

$98^{\circ}$

Option 2)

$128^{\circ}$

Option 3)

$203^{\circ}$

Option 4)

$45^{\circ}$

Posted by

Avinash

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