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A particle is oscillating on the X-axis with
an amplitude 2 cm about the point
x
0=10 cm, with a frequency ω. A concave
mirror of focal length 5 cm is placed at the
origin (see figure).


Identify the correct statements.
(A) The image executes periodic motion.
(B) The image executes non-periodic motion.
(C) The turning points of the image are asymmetric w.r.t. the image of the point at x=10 cm.


(D) The distance between the turning points of the oscillation of the image is \frac{100}{21}cm.
.

  • Option 1)

    (A), (D)

  • Option 2)

    (A), (C), (D)

  • Option 3)

    (B), (D)

  • Option 4)

    (B), (C)

 

Answers (1)

best_answer

As we learned

 

Mirror Formula -

\frac{1}{v}+\frac{1}{u}=\frac{1}{f}


 

- wherein

u= Object distance from pole of mirror.

v= Image distance from pole of mirror.

f= focal length of the mirror.

 

 For u = -10cm, f = -5cm

\frac{1}{v}=\frac{1}{8}-\frac{1}{u} = \frac{-1}{5} + \frac{1}{10} = \frac{-1}{10}cm

v = 10cm , u= -8cm & u = -12cm

u_{1}=-8cm

\frac{1}{v_{2}}= \frac{1}{f}-\frac{1}{u_{2}}= \frac{-1}{5}+\frac{1}{12}= \frac{-7}{60} or v_{2} = \frac{-60}{7}cm

difference between v_{1} and v_{2}

= v_{2}-v_{1} = \frac{-60}{7}+\frac{40}{3} = \frac{-180+280}{21}

= \frac{100}{21}cm 

 

for extreme on


Option 1)

(A), (D)

Option 2)

(A), (C), (D)

Option 3)

(B), (D)

Option 4)

(B), (C)

Posted by

Avinash

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