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  • Two beams of light having intensities I and interfere to produce a fringe pattern on a screen. The phase difference between the b

Two beams of light having intensities I and 9 \mathrm{I} interfere to produce a fringe pattern on a screen. The phase difference between the beams is \mathrm{\pi / 2} at point A and \mathrm{\pi} at point B. Then, the difference between the resultant intensities at A and B is:

Option: 1

2 I


Option: 2

6 I


Option: 3

5 I


Option: 4

7 I


Answers (1)

best_answer

Resultant intensity, \mathrm{I_R=I_1+I_2+2 \sqrt{I_1 I_2} \cos \phi}

thus difference is given by

\mathrm{\therefore \quad}  The difference between the intensity, \mathrm{\mathrm{I}_{\mathrm{A}}-\mathrm{I}_{\mathrm{B}}=6 \mathrm{I}}

Posted by

Gaurav

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