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Two Bus are approaching each other at an equal speed of 9.2 \mathrm{~km} / \mathrm{h}. When they see each other, both blow horn having frequency of 876 \mathrm{~Hz}. The beat frequency heard by each driver (velocity of sound in air is 332 \mathrm{~m} / \mathrm{s}. 

Option: 1

14Hz


Option: 2

12Hz


Option: 3

13Hz


Option: 4

16Hz


Answers (1)

best_answer

9.2 \mathrm{~km} / \mathrm{h}

=9.2 \times \frac{5}{18}=\frac{92 \times 5}{18 \times 10}=\frac{460}{180}=2.56 \mathrm{~m} / \mathrm{s}

f=876\left(\frac{332+2.56}{332-2.56}\right) \\

f=876 \times \frac{334.56}{329.44} \\

f=\frac{876 \times 33456}{32944}=\frac{29307456}{32944} \\

f=889.61 \\

 or  f=890 \mathrm{~Hz} \\

Beat frequency =890-876 =14 \mathrm{HZ}.

Posted by

shivangi.shekhar

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