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Two cells of emfs 3 \mathrm{v} and 1 \mathrm{v} \, \& internal resistances 0.3 \Omega \, \, \& \, \, 0.1 \Omega respectively as shown. Then

Option: 1

the current across 2 \Omega resistor is \frac{1}{2} \mathrm{~A}


Option: 2

current across 3V cell is zero


Option: 3

the terminal potential difference across the cells
is zero


Option: 4

current along 1V cell is zero.


Answers (1)

best_answer

The equivalent cell emf :

\varepsilon=\frac{\varepsilon_1 r_2+\varepsilon_2 r_1}{r_1+r_2}

Using this expression we obtain

\varepsilon=\frac{3 \times 0.1-1 \times 0.3}{0.1+0.3}=0

\text { Since } e_{\text {eff }}=0 \Rightarrow               \text { current across } 2 \Omega \text { resistor is zero }

\Rightarrow \quad \text { the current across each cell }=\frac{4 \mathrm{v}}{0.3+0.1}=10 \mathrm{amp}

V_{\text {terminal }}=3-0.3 \times 10=0

Posted by

shivangi.bhatnagar

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