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  • Two circular coils X and Y have equal number of turns and carry equal currents in the same sense and subtend same solid angle at point O. If the smaller coil X is midway between O and Y, then if we

Two circular coils X and Y have equal number of turns and carry equal currents in the same sense and subtend same solid angle at point O. If the smaller coil X is midway between O and Y, then if we represent the magnetic induction due to bigger coil Y at O as by and that due to smaller coil X at O as Bx, then:

Option: 1

\frac{\mathrm{B}_{\mathrm{y}}}{\mathrm{B}_{\mathrm{x}}}=1


Option: 2

\mathrm{\frac{B_y}{B_x}=2}


Option: 3

\frac{\mathrm{B}_{\mathrm{y}}}{\mathrm{B}_{\mathrm{x}}}=\frac{1}{2}


Option: 4

\frac{\mathrm{B}_{\mathrm{y}}}{\mathrm{B}_{\mathrm{x}}}=\frac{1}{4}


Answers (1)

best_answer

Radius of coil ' y ' =2 \times$ Radius of coil ' x '.

\mathrm{B_y=\frac{\mu_0}{4 \pi} \frac{2 \pi l(2 r)^2}{\left((2 r)^2+(2 d)^2\right)^{3 / 2}} \\ }

\mathrm{ B_x=\frac{\mu_0}{4 \pi} \frac{2 \pi l(r)^2}{\left(\left(r^2\right)+(d)^2\right)^{3 / 2}} \\ }

\mathrm{ \frac{B_y}{B_x}=\frac{4}{4^{3 / 2}}=\frac{1}{2} }.

Posted by

Deependra Verma

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