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Two coils of self inductance \mathrm{L_{1}\: and\: L_{2}} are connected in series combination having mutual inductance of the coils as \mathrm{M}. The equivalent self inductance of the combination will be :

 

Option: 1

\mathrm{\frac{1}{L_{1}}+\frac{1}{L_{2}}+\frac{1}{M}}


Option: 2

\mathrm{L_{1}+L_{2}+M}


Option: 3

\mathrm{L_{1}+L_{2}+2M}


Option: 4

\mathrm{L_{1}+L_{2}-2M}


Answers (1)

best_answer


\rightarrow Flux due to coil 1 and coil 2 are in opposite direction 

\rightarrow The current is same through both the coil

\mathrm{\therefore L_{eq}= L_{1}+L_{2}-2M}

The correct option is (4)
 

Posted by

HARSH KANKARIA

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