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Two coins are simultaneously tossed. The probability of two heads simultaneously appearing

Option: 1

\frac{1}{8}


Option: 2

\frac{1}{6}


Option: 3

\frac{1}{4}


Option: 4

\frac{1}{2}


Answers (1)

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Set of possible outcomes 

                             =\{(\mathrm{HH}),(\mathrm{HT}),(\mathrm{TH}),(\mathrm{TT})\}

Set of favourable outcomes =\{(\mathrm{HH})\}

\therefore The required probability  =\frac{1}{4}

                                       

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rishi.raj

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