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  • Two concentric coils each of radius equal to cm are placed at right angles to each other. 3 A and 4 A are the current

Two concentric coils each of radius equal to 2\pi cm are placed at right angles to each other. 3 A and 4 A are the currents flowing in each coil, respectively. The magnetic induction in {\mathrm{Wb} / \mathrm{m}^2} at the centre of the coils will be \mathrm{\left(\mu_0=4 \pi \times 10^{-7} \mathrm{~Wb} / \mathrm{A}-\mathrm{m}\right)}

Option: 1

\mathrm{12 \times 10^{-5}}


Option: 2

\mathrm{10^{-5}}


Option: 3

\mathrm{5 \times 10^{-5}}


Option: 4

\mathrm{7 \times 10^{-5}}


Answers (1)

best_answer

Magnetic field at P, \mathrm{\mathrm{B}_1=\frac{\mu_0 \mathrm{I}_2}{2 \mathrm{R}}=\frac{4 \pi \times 10^{-7} \times 4}{2 \times 0.02 \pi}=4 \times 10^{-5} \mathrm{~Wb} / \mathrm{m}^2}

Magnetic field, at Q, \mathrm{B_2=\frac{\mu_0 I}{2 R}=\frac{4 \pi \times 10^{-7} \times 3}{2 \times 0.02 \pi}=3 \times 10^{-5} \mathrm{~Wb} / \mathrm{m}^2}

\mathrm{\therefore \quad B=\sqrt{B_1^2+B_2^2}=\sqrt{\left(4 \times 10^{-5}\right)^2+\left(3 \times 10^{-5}\right)^2}=5 \times 10^{-5} \mathrm{~Wb} / \mathrm{m}^2}

 

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Riya

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