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  • Two cylindrical rods of uniform cross-sectional area and 2, having free electrons per unit volume 2 and , respectively, are joined in series. A current flows through them in steady state. Then the

Two cylindrical rods of uniform cross-sectional area and 2, having free electrons per unit volume 2 and , respectively, are joined in series. A current flows through them in steady state. Then the ratio of drift velocity o free electron in left rod to drift velocity of electron in the right rod (1/) is

Option: 1

\frac{1}{2}


Option: 2

1


Option: 3

2


Option: 4

4


Answers (1)

best_answer

Since current IneAv \mathrm{v_d} through both the rods is the same,

\begin{aligned} & \text { i.e. } \mathrm{2(n) e A v_L=n e(2 A) v_R }\\ & \Rightarrow \mathrm{\frac{v_L}{v_R}=1} \end{aligned}

Posted by

Sanket Gandhi

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