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Two dice are thrown. What is the probability that the sum of the numbers on the two dice is eight?

Option: 1

\frac{5}{36}


Option: 2

\frac{5}{18}


Option: 3

\frac{1}{4}


Option: 4

\frac{1}{3}


Answers (1)

best_answer

Favourable Cases 

                         \begin{aligned} & =\{(6,2),(2,6),(5,3),(3,5),(4,4) \\ & =5 \end{aligned}

Total Cases

                        \begin{gathered} =36=\{(1,1),(1,2),(1,3), \\ (2,1),(2,2), \ldots .(6,6)\} \end{gathered}

So, required probability

                         =\frac{5}{36}

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Gunjita

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