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  • Two electric bulbs rated 50 W and 100 W are glowing at full power, when used in parallel with a battery of emf 120 V and internal resistance <img alt="10\; \Omega" src="https://entrancecorner.oncod

Two electric bulbs rated 50 W and 100 W are glowing at full power, when used in parallel with a battery of emf 120 V and internal resistance 10\; \Omega . The maximum number of bulbs that can be connected in the circuit when glowing at full power, is:

Option: 1

6


Option: 2

4


Option: 3

3


Option: 4

8


Answers (1)

best_answer

Maximum current possible in bulb =\frac{50}{100}=0.5 \mathrm{~A}

Resistance of each bulb =\frac{\mathrm{V}^2}{\mathrm{P}}=\frac{100 \times 100}{50}=200 \Omega

If n be the number of bulb possible, then total resistance of circuit =\frac{200}{\mathrm{n}}+10

Maximum current in the circuit =0.5 \times \text{n}

So     \frac{120}{\frac{200}{\mathrm{n}}+10}=0.5 \mathrm{n} \Rightarrow \mathrm{n}=4

Posted by

Sanket Gandhi

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