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  • Two identical short magnetic dipoles of magnetic moments  <img alt="1.0 \mathrm{~A}-\mathrm{m}^2" src="https://entrancecorner.oncodecogs.com/gif.latex?1.0%20%5Cmathrm%7B%7EA%7D-%5Cmathrm%

Two identical short magnetic dipoles of magnetic moments  1.0 \mathrm{~A}-\mathrm{m}^2 each, placed at a separation of  2 \mathrm{~m} with their axes perpendicular to each other. The resultant magnetic field at a point midway between the dipole is:

Option: 1

5 \times 10^{-7} \mathrm{~T}


Option: 2

\sqrt{5} \times 10^{-7} \mathrm{~T}


Option: 3

10^{-7} \mathrm{~T}


Option: 4

2 \times 10^{-7} \mathrm{~T}


Answers (1)

best_answer


\therefore \quad \mathrm{B}_1=\frac{\mu_0}{4 \pi} \frac{2 \mathrm{M}}{\mathrm{d}^3}=\frac{10^{-7} \times 2 \times 1}{1^3}=2 \times 10^{-7}

\mathrm{B}_2=\frac{\mu_0}{4 \pi} \frac{\mathrm{M}}{\mathrm{d}^3}=10^{-7}

B_{net}=\sqrt{\mathrm{B}_1^2+\mathrm{B}_2^2}=\sqrt{5} \times 10^{-7} \mathrm{~T}

Posted by

shivangi.shekhar

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