Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Two isolated conducting spheres S1 and S2 of radius  have <img alt="12

Two isolated conducting spheres S1 and S2 of radius  \frac{2}{3}Rand \frac{1}{3}R have 12 \mu C and -3\mu C charges respectively and are at a large distance from each other. They are now connected by a conducting wire. A long time after this is done the charges on   S1 andS2 are respectively
 
Option: 1 + 4.5\mu C\; and\; + 4.5\mu C
Option: 2 + 4.5\mu C\; and\; - 4.5\; \mu C
Option: 3 + 3\mu C\; and\; +6\; \mu C  
Option: 4 + 6\mu C\; and\; +3\; \mu C

Answers (1)

best_answer

After connecting with wires, there will be charge flow such that the potential of both spheres are equal.

Let the flow of charge be q from (1) to (2)

So, final charge on (1)=(12-q)\mu C

and, final charge on (2)=(-3+q)\mu C

So,

V_{1}=V_{2}

\frac{k(12-q)}{(2R / 3)}=\frac{k(q-3)}{(R / 3)}

\begin{aligned} 12-q &=2q-6 \\ 3 q=& 18 \\ \Rightarrow q=6 \mu C \\ So, \\ Q_{1}=& 12-6=6 \mu \mathrm{c} \\ Q_{2}=&-3+6=3 \mathrm{\mu C} \end{aligned}

Posted by

avinash.dongre

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: BTech CSE cut-offs for PwD candidates at NITs make entry easy; top institutes still selective
anam-khan

73 or 99 percentile? JEE Main result questioned, J-K candidate says, ‘Don’t create hype’
anam-khan

JEE Main 2025: 11 from Kota coaching centres among 24 students with 100 percentile

Latest Question