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Two liquids A and B on mixing produce a warm solution. Which type of deviation from Raoult's law does it show?

Option: 1

Negative deviation


Option: 2

Positive deviation


Option: 3

Can't say anything


Option: 4

Data insufficient


Answers (1)

best_answer

Warming up of the solution means that the process of mixing is exothermic, i.e., \Delta_{\text {mixing }} \mathrm H \mathrm{\: is\: negative}.
This implies that the solution shows a negative deviation.

Therefore, option(1) is correct 

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manish

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