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Two opposite and equal charges 4 \times 10^{-8} \mathrm{C}  when placed 2 \times 10^{-2} \mathrm{~cm} away, from a dipole. If this dipole is placed in an external electric field 4 \times 10^{8} \mathrm{~N} / \mathrm{C},  the value of maximum torque-

Option: 1

64 \times 10^{-4} \mathrm{Nm}


Option: 2

32 \times 10^{-4} \mathrm{Nm}


Option: 3

264 \times 10^{-4} \mathrm{Nm}


Option: 4

6.32 \times 10^{-4} \mathrm{Nm}


Answers (1)

best_answer

we know that,
p=q \cdot l=4 \times 10^{-8} \times 2 \times 10^{-4}
p=8 \times 10^{-12} \mathrm{~cm}

\text { Max } .\text { torque } \tau_{\text {max }} =P E
                                         =8 \times 10^{-12} \times 4 \times 10^{8}
                                         =32 \times 10^{-4} \mathrm{Nm}  Ans.

Posted by

Gautam harsolia

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