Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

Two parallel, long wires carry current i1 and i2 with i1 > i2. When the current is in the same direction, the magnetic field at a point midway between the wire is $10\mu T$ . If the direction of i2 is reversed, the field becomes $30\mu T$ . The ratio of i1/ i2 is:
Option: 1
4

Option: 2
3

Option: 3
2

Option: 4
1

Answers (1)

best_answer

$B_{net} = \frac{\mu_{0} (i1 - i2)}{2\pi d} = 10 \mu T$

$\vec{B} = \frac{\mu_{0} (i1 + i2)}{2\pi d} = 30 \mu T$

Solving both equations, we get:

$\frac{i1}{i2} = 2$

Posted by

shivangi.bhatnagar

View full answer

Similar Questions

5 g of Na₂SO₄ was dissolved in x g of H₂O. The change in freezing point was found to be 3.82⁰C. If Na₂SO₄ is 81.5% ionised, the value of x (K

A capacitor is made of two square plates each of side 'a' making a very small angle $\alpha$

A solution of m-chloroaniline, m-chlorophenol and m-chlorobenzoic acid in ethyl acetate was extracted initially with a saturated solution of NaHCO₃ to give fraction A. The leftover organic phase was extracted with d

Latest Question