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Two points\mathrm{ P (a, 0) } and\mathrm{ Q (-a, 0) } are given. \mathrm{ R } is a variable point on one side of the line \mathrm{ PQ } such that \mathrm{ \angle RPQ - } \mathrm{ \angle RQP} is a\mathrm{ 2\alpha } . Find the locus of \mathrm{ R }.

 

Option: 1

\mathrm{x^{2}+y^{2}-2xy\ cot \ 2x+a^{2}=0}


Option: 2

\mathrm{x^{2}+y^{2}+2xy\ cot \ \alpha -a^{2}=0}


Option: 3

\mathrm{x^{2}+y^{2}+2xy\ cot\ 2\alpha -a^{2}=0}


Option: 4

None of these 


Answers (1)

best_answer

Let \mathrm{R(h, k)}  be the variable point (see figure). Then \mathrm{\angle RPQ = \Theta }  and \mathrm{\angle RQP = \varphi , }so that\mathrm{ \Theta -\varphi } \mathrm{ = 2\alpha }. Let RM\mathrm{ \perp PQ } , so that \mathrm{ RM = k, }

\mathrm{ MP=a-h } and \mathrm{ MQ = a + h. }
Then \mathrm{ tan \Theta = } \mathrm{ \frac{RM}{MP}=\frac{k}{a-h} } and \mathrm{tan\varphi =\frac{RM}{MQ}=\frac{k}{a+h}}
\mathrm{\therefore } from \mathrm{2\alpha = \Theta - \alpha }
\mathrm{tan\ 2\alpha=tan \left ( \Theta -\varphi \right ) = } \mathrm{\frac{tan \Theta -tan \phi }{1+tan\Theta \ tan\phi }=}\mathrm{\frac{k\left ( a+h \right )-k\left ( a-h \right )}{a^{2}-h^{2}+k^{2}}}

 

\mathrm{\Rightarrow a^{2} - h^{2} + k^{2} = 2hk\ cot\ 2\alpha }
 

Hence, the locus of \mathrm{R(h, k) } is \mathrm{ x2 - y2 + 2xy\ cot 2\alpha - a^{2} = 0. }

 

 

 

 

Posted by

Gautam harsolia

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