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Two resistors 400 ohm and 800 ohm are connected in series with a 6V battery. It is desired to measure the current in the circuit. An ammeter of 10 ohm resistance is used for this purpose. The reading in the ammeter is:

Option: 1

2.7mA 


Option: 2

3.5mA


Option: 3

4.36mA 


Option: 4

4.96mA


Answers (1)

best_answer

When ammeter of 10\Omega is put in series in the circuit, the reading will be

\mathrm{i}=\frac{6}{(400+800+10)}=\frac{6}{1210} \mathrm{~A}=4.96 \mathrm{~mA}

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Deependra Verma

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