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  • Two resistors 400 ohm and 800 ohm are connected in series with a 6V battery. It is desired to measure the current in the circuit. An ammeter of 10 ohm resistance is used for this purpose. The readi

Two resistors 400 ohm and 800 ohm are connected in series with a 6V battery. It is desired to measure the current in the circuit. An ammeter of 10 ohm resistance is used for this purpose. The reading in the ammeter is:

Option: 1

2.7mA 


Option: 2

3.5mA


Option: 3

4.36mA 


Option: 4

4.96mA


Answers (1)

best_answer

When ammeter of 10\Omega is put in series in the circuit, the reading will be

\mathrm{i}=\frac{6}{(400+800+10)}=\frac{6}{1210} \mathrm{~A}=4.96 \mathrm{~mA}

Posted by

Deependra Verma

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