Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Two sources of sound A and B produce the wave of 35 Hz, in the same phase . The particle P is vibrating under the influence of these two waves , if the amplitude at the point P produces by the two

Two sources of sound A and B produce the wave of 35 Hz, in the same phase . The particle P is vibrating under the influence of these two waves , if the amplitude at the point P produces by the two waves is 0.3 mm and 0.4 mm. Then, the resulatant amplitude of the point P will be when \mathrm{AP-BP=25 \; cm} and the velocity of sound is 350 m/s

Option: 1

0.7 mm


Option: 2

0.1 mm


Option: 3

0.2 mm


Option: 4

0.5 mm


Answers (1)

best_answer

\mathrm{\lambda=\frac{v}{n}=\frac{350}{350}=1 \mathrm{~m}=100 \mathrm{~cm} .}

Also, path difference \mathrm{(\Delta x)} between the waves at the point of observation is \mathrm{AP-BP=25 \; cm}

\begin{aligned} \Delta \phi & =\frac{2 \pi}{\lambda} \cdot(\Delta x) \\ & =\frac{2 \pi}{1} \times\left(\frac{25}{100}\right)=\frac{\pi}{2} \\ A & =\sqrt{\left(a_1\right)^2+\left(a_2\right)^2} \\ A & =\sqrt{(0.3)^2+(0.4)^2} \\ A & =0.5 \mathrm{~mm} \end{aligned}

Posted by

Deependra Verma

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: JCECEB invites fresh applications for Jharkhand state merit list correction

Latest Question