Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

Two spheres of mass 'm' but of densities \rho _{1} and \rho_{2}   (\rho_{2}> \rho_{1})  are connected by a string and the combination is immersed in liquid (\rho_{l}). The tension in the string will be - 

Option: 1

\frac{m\rho_{l}g}{2}[\frac{1}{\rho_{1}}-\frac{1}{\rho_{2}}]


Option: 2

m\rho_{l}g[\frac{1}{r_{1}}-\frac{1}{r_{2}}]


Option: 3

\frac{m\rho_{l}g}{2}[\frac{1}{\rho_{2}}-\frac{1}{\rho_{1}}]


Option: 4

m\rho_{l}g[\frac{1}{r_{2}}-\frac{1}{r_{1}}]


Answers (1)

best_answer

For the equilibrium 

T = Fb1-mg    - (1)

T=mg-Fb2     - (2)

from above equation we get, 

T=\frac{F_{b1}-F_{b2}}{2}\\T=\frac{v_{1}\rho_{l}g-v_{2}\rho_{l}g}{2}\\T=\frac{m\rho_{l}g}{2}[\frac{1}{\rho_{1}}-\frac{1}{\rho_{2}}]

Posted by

Pankaj

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 paper 2 final answer key out; NTA drops 4 questions, 2 from BPlanning
anam-khan

JEE Main 2025 session 2 answer key out for BArch, BPlanning; response sheet on jeemain.nta.nic.in
anam-khan

JEE Mains 2025 Paper 2 Answer Key LIVE: BArch final answer key PDF expected soon at jeemain.nta.nic.in

Latest Question