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  • Two spherical balls having equal masses with a radius of 5 cm each are thrown upward along the same vertical direction at an interval of 3 s with the same initial velocity of 35 m/s, then these balls collide at a height of ----- m. (take g = 10 m/s

Two spherical balls having equal masses with a radius of 5 cm each are thrown upward along the same vertical direction at an interval of 3 s with the same initial velocity of 35 m/s, then these balls collide at a height of ----- m.
(take g = 10 m/s2)
 

Answers (1)

best_answer


Ball 2 is projected 3 s after ball 1
Let say they collide after t s of projection of ball 1
For ball 1
s= ut+\frac{1}{2}at^{2}
s_{1}= 35t\; \;-\frac{1}{2}gt^{2}\rightarrow \left ( 1 \right )
For ball 2
s_{2}= 35\left ( t-3 \right )\: -\frac{1}{2}g\left ( t-3 \right )^{2}\rightarrow \left ( 1 \right )
At collision , s_{1}= s_{2}
3gt\; \; - \frac{1}{2}gt^{2}= 35t-105\: \:- \frac{1}{2}g\left ( t^{2}- 6t+9\right )
{30t}\;- \frac{1}{2}{gt^{2}}={30t}-105 \:- \frac{1}{2}{gt^{2}}+3gt\: -\frac{9g}{2}
105\: -\frac{9g}{2}= 3gt
60= 30t
t= 25
s_{1}= 35\times 2\: \frac{-1}{2}\times 10\times \left ( 2 \right )^{2}
s_{1}= 70-20= 50 \, m

Posted by

vishal kumar

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