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  • Under the condition of weightlessness due to rotation of earth at equator time period of earth will beOption: 1 <img alt="\frac{1}{15}" src="/latex-i

Under the condition of weightlessness due to rotation of earth at equator time period of earth will be

Option: 1

\frac{1}{15} times of present time period of earth.


Option: 2

\frac{1}{19} times of present time period of earth.


Option: 3

\frac{1}{21} times of present time period of earth.


Option: 4

\frac{1}{17} times of present time period of earth.


Answers (1)

best_answer

As we learnt

 

Time period of Rotation of earth -

 

T=\frac{2\pi }{\omega }=2\pi \sqrt{\frac{R}{g}}

R\rightarrow Radius of earth

T\rightarrow Time period of  rotation of earth
 

- wherein

R=6400\times 10^{3}m

g=10\: m/s^{2}

T=1.40\; hr

\omega =\frac{1}{800}\frac{rad}{sec}

 

 

Time period of Rotation of earth -

T=\frac{2\pi }{\omega }=2\pi \sqrt{\frac{R}{g}}= 2*3.14*\sqrt{\frac{6400*10^3}{10}}

T=5026.5sec\approx 1.4hr

Present time of earth rotation = 24hr

so 24/1.4=17 times

Hence due to rotation time period could be 1/17 th times of present time period.

Posted by

chirag

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