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Using a current of 3.62A if 0.60L of a 0.60M} \mathrm{SnSO_4} solution is electrolyzed for a period of 28min. If inert electrodes are used, what is final concent ration of \mathrm{\mathrm{Sn}^{2+}} remaining in the solution.

Option: 1

0.219 M


Option: 2

1.842 M


Option: 3

0.642 M


Option: 4

0.548 M


Answers (1)

best_answer

\mathrm{\frac{\omega}{M} \times 2 = \frac{3.62 \times 28 \times 60}{96500}}

\mathrm{\text { Moles of } \mathrm{Sn}^{2+} \text { reduced }=0.031}

\mathrm{Initial ~moles ~of \mathrm{~Sn}^{2^{+}} ~reduced =0.6 \times 0.6 }

                                                                \mathrm{=0.36}

\mathrm{ \text { remaining moles of } \mathrm{Sn}^{2+} =0.36-.0 .031 \\ }

                                                       \mathrm{ =0.329 }

 \mathrm{ \operatorname{Sn}^{2 +}=\frac{0.329}{0.6} }

\mathrm{ =0.5483 }

Posted by

seema garhwal

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