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  • Wavelength of light used in an optical instrument are =4000<img alt="\dot{A}" src="https://learn.careers36

Wavelength of light used in an optical instrument are \lambda_{1}=4000\dot{A} and  \lambda_{2}=5000 \dot{A}, then ratio of their respective resolving powers ( corresponding to \lambda_{1} \ and \ \lambda_{2}) is - 

Option: 1

16:25


Option: 2

9:1


Option: 3

4:5


Option: 4

5:4


Answers (1)

best_answer

 

 

\begin{array}{l}{\text { Resolving power is proportional to } \lambda^{-1}} \\ \\ {\therefore \quad \frac{R . P \text { for } \lambda_{1}}{R . P . \text { for } \lambda_{2}}=\frac{\lambda_{2}}{\lambda_{1}}=\frac{5000}{4000}=\frac{5}{4}}\end{array}

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