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Question

Asked in: JEE-2006

Consider a two particle system with particles having masses  m1 and m2 . If the first particle is pushed  towards the centre of mass through a distance  d, by what distance should the second particle be moved, so as to keep the centre of mass at the same position ?

 Your option is incorrect !!

A.

d

B.

\frac{m_{2}}{m_{1}}d

C.

\frac{m_{1}}{m_{1}+m_{2}}d

D.

\frac{m_{1}}{m_{2}}d

Answers (1)

 \Delta x_{cm}=\frac{m_{1}.\Delta x_{1}+m_{2}.\Delta x_{2}}{m_{1}+m_{2}}

Let m_{2} be moved by x so as to keep the centre of mass at the same position

\Delta x_{1}=-d and \Delta x_{CM}=0

\therefore \; \; \; m_{1}(-d)+m_{2}(x_{2})=0,

or\; \; \; m_{1}d=m_{2}x_{2}; \; \; or\; \; \; x_{2}=\frac{m_{1}}{m_{2}}d

Posted by

Safeer PP

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