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  • What is the appropriate change in the density of water in a lake at a depth of 400 m below the surface?  The density of water at the surface is 1030 <img alt="Kg/m^{3}" src="https://entra

What is the appropriate change in the density of water in a lake at a depth of 400 m below the surface?  The density of water at the surface is 1030 Kg/m^{3} and bulk mosulous of water is 2\times 10^{9}N/m^{2}.

Option: 1

4\ Kg/m^{3}


Option: 2

2\ Kg/m^{3}


Option: 3

6\ Kg/m^{3}


Option: 4

8\ Kg/m^{3}


Answers (1)

best_answer

\\d\rho=\frac{\rho}{\beta }\ d\rho \\\\d\rho=\rho\ g\ h=1030\times 10\times 400 \\\\=4.12\times 10^{6} N/m^{2}

\therefore d \rho =\frac{1030}{2\times10^{9}}\times 4.12\times 10^{6}

d\rho =2.12\ Kg/m^{3}

d\rho =2\ Kg/m^{3}

 

Posted by

manish painkra

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