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  • What is the chance that a leap year, selected at random, will contain 53 Saturdays?Option: 1 <img alt="\frac{2}{7}" src="https://entrancecorner.oncod

What is the chance that a leap year, selected at random, will contain 53 Saturdays?

Option: 1

\frac{2}{7}


Option: 2

\frac{3}{7}


Option: 3

\frac{1}{7}


Option: 4

\frac{5}{7}


Answers (1)

best_answer

Number of days in a leap year =366

\begin{aligned} & =7 \times 52+2 \\ & =52 \text { weeks and } 2 \text { days } \end{aligned}
These 2 day can be
Case (i):Mon and Tue
Case (ii):Tue and Wed
Case (iii):Wed and Thu
Case (iv):Thu and Fri
Case (v):Fri and Sat
Case (vi):Sat and Sun
Case (vii):Sun and Mon
Out of above seven cases, case (v) and case (vi) are the two favorable cases.

\therefore  The required probability
=\frac{2}{7}

 

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