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  • What is the De-Broglie wavelength of a proton moving at a velocity of ?<div clas

What is the De-Broglie wavelength of a proton moving at a velocity of 2.5\times10^{6}m/s?

Option: 1

0.00016 nm


Option: 2

0.00032 nm


Option: 3

0.00064 nm


Option: 4

0.00128 nm


Answers (1)

best_answer

Using the equation,
\lambda = \frac{h}{p}
where h is the Planck's constant, p is the momentum of the particle.
Given, v= 2.5\times 10^{6}m/s,m = mass of proton, h = Planck's constantThe momentum of proton,p= m \times v
Putting the values, we get
\lambda =6.626\times 10^{-34} /\left ( 1.67\times10^{-27}\times2.5\times10^{6} \right )= 0.00016nm.

Posted by

SANGALDEEP SINGH

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