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  • What is the equation of a circle with a centre (2,3) and radius of 5?Option: 1 <img alt="\left ( x-2 \right )^{2}+\left ( y-3 \right )^{2}= 5^{2}" sr

What is the equation of a circle with a centre (2,3) and radius of 5?

Option: 1

\left ( x-2 \right )^{2}+\left ( y-3 \right )^{2}= 5^{2}


Option: 2

\left ( x+\: 2 \right )^{2}+\left ( y+3 \right )^{2}= 5^{2}


Option: 3

\left ( x-2 \right )^{2}+\left ( y+3 \right )^{2}= 5^{2}


Option: 4

\left ( x+ 2 \right )^{2}+\left ( y-3 \right )^{2}= 5^{2}


Answers (1)

best_answer

The equation of a circle with centre (h,k) and radius r is given by \left ( x-h \right )^{2}+\left ( y-k \right )^{2}= r^{2}.
Here,
h= 2
k= 3
r= 5
Substituting the given values, we get:

\left ( x-2 \right )^{2}+\left ( y-3 \right )^{2}= 5^{2}

 

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Sayak

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