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  • What is the equation of a circle with a centre (-4,2) and radius of 7?Option: 1 <img alt="\left ( x+4 \right )^{2}+\left ( y+2 \right )^{2}= 7^{2}" s

What is the equation of a circle with a centre (-4,2) and radius of 7?

Option: 1

\left ( x+4 \right )^{2}+\left ( y+2 \right )^{2}= 7^{2}


Option: 2

\left ( x-4 \right )^{2}+\left ( y-2 \right )^{2}= 7^{2}


Option: 3

\left ( x+4 \right )^{2}+\left ( y-2 \right )^{2}= 7^{2}


Option: 4

\left ( x-4 \right )^{2}+\left ( y+2 \right )^{2}= 7^{2}


Answers (1)

best_answer

The equation of a circle with centre (h,k) and radius r is given by \left ( x-h \right )^{2}+\left ( y-k \right )^{2}= r^{2}

Here,
h= -4
k= 2
r= 7

Substituting the given values, we get:

\left ( x+4 \right )^{2}+\left ( y-2 \right )^{2}= 7^{2}

Posted by

jitender.kumar

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