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  • What is the equation of minor axis of the ellipse <img alt="4x^2+9y^2-48x+72y+144=0" src="https://entrancecorner.oncodecogs.com/gif.latex?4x%5E2&plus;9y%5E2-48x&plus;72y&plus;144%3

What is the equation of minor axis of the ellipse 4x^2+9y^2-48x+72y+144=0?

Option: 1

y=4


Option: 2

y=-4


Option: 3

x=6


Option: 4

x=-6


Answers (1)

best_answer

As we learnt

 

Minor axis -

 

The line segment through the centre and perpendicular to the major axis.

- wherein

 

  4x^2+9y^2-48x+72y+144=0

4(x^2-12x)+9(y^2+8y)+144=0

4(x-6)^2+9(y+4)^2=144

\frac{(x-6)^2}{36}+\frac{(y+4)^2}{16}=1

Thus the centre is x=6,y=-4

 

 

Posted by

HARSH KANKARIA

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