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  • What is the kinetic energy of an electron emitted from a metal surface when the frequency of the incident radiation is <img alt="1.2\times 10^{15}Hz" src="https://entrancecorner.oncodecogs.com

What is the kinetic energy of an electron emitted from a metal surface when the frequency of the incident radiation is 1.2\times 10^{15}Hz and the work function of the metal is 1.8 eV?

Option: 1

5 eV


Option: 2

3.2 eV


Option: 3

120 eV


Option: 4

9 eV


Answers (1)

best_answer

The kinetic energy of an electron emitted from a metal surface by incident radiation is given by the equation

KE= h\nu-\phi,

where, h is Planck's constant,  \nu is the frequency of the incident radiation, and \phi  is the work function of the metal.

Substituting the given values, we get
K E=\left(6.626 \times 10^{-34} \mathrm{Js}\right)\left(1.2 \times 10^{15} \mathrm{~Hz}\right)-(1.8 \mathrm{eV})=3.2\ \mathrm{eV}.

Posted by

Gautam harsolia

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