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What is the maximum distance of (4,3) from x^2 + y^2 = 4 ?

Option: 1

4


Option: 2

5


Option: 3

6


Option: 4

7


Answers (1)

best_answer

First, check if the point (4,3) lies inside or outside of the circle

4^2+3^2-4=21>0

(4,3) lies outside the circle

so maximum distance is CP + r

CP = 5

r = 2

CP + r = 7

Posted by

seema garhwal

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