Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • What is the value of Gibbs energy if the entropy of an ideal gas is the function of its temperature as <img alt="\mathrm{S=3+10^{-2} T(J / K)}" src="https://entrancecorner.oncodecogs.com/gif.latex?

What is the value of Gibbs energy if the entropy of an ideal gas is the function of its temperature as \mathrm{S=3+10^{-2} T(J / K)} and at \mathrm{1} atom and \mathrm{-70^{\circ} \mathrm{C}}, the gas was stored in a \mathrm{25 \mathrm{~L}} sealed rigid container and heated so that the temperature changed to \mathrm{25^{\circ} \mathrm{C}(1 \mathrm{~atm} . \mathrm{L}=0.1 \mathrm{~kJ})}

Option: 1

\mathrm{795.3\ J}


Option: 2

104\ \mathrm{J}


Option: 3

\mathrm{606.8\ J}


Option: 4

\mathrm{5432\ J}


Answers (1)

best_answer

\mathrm{\text { At constant volume, } \frac{P_1}{T_1}=\frac{P_2}{T_2}}
\mathrm{\begin{aligned} P_2 & =\mathrm{P_1 \times \frac{T_2}{T_1}} \\ & =\mathrm{\frac{1 \times 293}{203}=1.44} \\ \mathrm{V_1} & =25 \mathrm{~L} \end{aligned}}
\mathrm{For\ single\ phase\ d G=V d p-S d T} \\ \mathrm{\Delta G=V \Delta P-\int\left(3+10^{-2} T\right) d T}
\begin{aligned} & =\mathrm{25(1.44-1) a t m L-\int\left(3+10^{-2} T\right) d T }\\ & =\mathrm{1100-\left[3 T-10^{-2} \frac{T^2}{2}\right]^{T_2}} \end{aligned}
\begin{aligned} & =1100-3(90)-\frac{10^{-2}}{2}[85849-41209] \\ & =1100-270-223.2 \\ & =606.8 \mathrm{~J} \end{aligned}

Posted by

vishal kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 final key soon; objection window closes today
anam-khan

100 marks in JEE Mains 2026 Percentile: Know rank trends, admission chances at NITs, IIITs
anam-khan

NIT vs GFTI: Which requires a lower JEE Main cutoff?

Latest Question