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What orbitals are used in forming \mathrm{ [BeF_4]^{2-}} complexes from \mathrm{ [BeF_2]}?

Option: 1

\mathrm{2s}


Option: 2

\mathrm{2p}


Option: 3

\mathrm{2s\: and\: 2p}


Option: 4

\mathrm{3d}


Answers (1)

best_answer

\mathrm{ Be^{2+}} in in excited state has the configuration \mathrm{1s^{2}2s^{1}2p^{1}}. In \mathrm{BeF_2} the two electrons from fluorine are present in one \mathrm{s } and one \mathrm{ p} orbital forming pair with the excited electrons. To accommodate two more fluorine anions, \mathrm{BeF_2} undergoes \mathrm{sp } hybridisation and the remaining \mathrm{ 2p} orbitals are free for \mathrm{ F^{-}} ions to donate their electrons.

Hence option 2 is correct.

 

Posted by

Kuldeep Maurya

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