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  • What will be the relative molecular mass of benzene in victor miyer determination method where <img alt="\mathrm{125^{\circ} \mathrm{C}}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmat

What will be the relative molecular mass of benzene in victor miyer determination method where \mathrm{125^{\circ} \mathrm{C}} temperature was maintained for the heating container. \mathrm{0.1852 \mathrm{~g}} of benzene was taken is it was observed that \mathrm{50 \mathrm{~cm}^3} of displaced air was collected over water (V.p. of water \mathrm{=14 \mathrm{mmHg}} ) at \mathrm{18^{\circ} \mathrm{C}}. The barometric pressure was \mathrm{782 \mathrm{~mm} \mathrm{Hg}.}

Option: 1

87.46 g


Option: 2

78 g


Option: 3

93.26 g


Option: 4

65.41 g


Answers (1)

\mathrm{\text { Actual pressure of displaced } ai r=782-14}

                                                                     \mathrm{\begin{aligned} & =768 \mathrm{~mm}\, \, \mathrm{Hg} \\ & =\frac{768}{760} \mathrm{~atm} \end{aligned}}

\mathrm{18^{\circ} \mathrm{C}=18+273}

            \mathrm{=291 \mathrm{~K}}

\mathrm{V=50 \mathrm{~cm}^3=50 \times 10^{-3} \mathrm{~L}}

\mathrm{w=0.1852 \mathrm{~g}}

\mathrm{\therefore M=\frac{W R T}{P V}}

\mathrm{=\frac{0.1852 \times 0.082 \times 291}{\frac{768}{760} \times 0.050}}

\mathrm{=87.46 \mathrm{~g}}

Posted by

Sumit Saini

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