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What will the ratio of weight of \mathrm{Ag} / \mathrm{Cu}  deposited on Pt electrode if One Column of charge passes through solution of  \mathrm{AgNO_3} and  \mathrm{\mathrm{CuSO_4}}  connected in series and the concentration of the two solution being in the  ratio 2:3.

Option: 1

22.4: 36.86 


Option: 2

66.2: 35.6


Option: 3

 53.95: 21.18 


Option: 4

 41.8: 36.2
 


Answers (1)

best_answer

Faraday' second law W/E = constant
\mathrm{ \frac{W_{\text {Ag }}}{E_{\text {Ag }}}=\frac{W_{\text {Cu }}}{E_{\text {Cu}}}\left(\mathrm{Ag}^{+}+e^{-} \rightarrow \mathrm{Ag}, \mathrm{[Ag}^{-}=\frac{\mathrm{M}}{1}]\right) }
\mathrm{ \frac{W_{\mathrm{Ag}}}{E_{\mathrm{Ag}}}=\frac{W_{\mathrm{Cu}}}{E_{\mathrm{Cu}}}=\frac{107.9 / 2}{63.54 / 3}=\frac{53.95}{21.18} \\ }.

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