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  • When 0.01 mol of an organic compound containing 60% carbon was burnt completely, 4.4 g of 

When 0.01 mol of an organic compound containing 60% carbon was burnt completely, 4.4 g of  \mathrm{CO}_2 was produced. The molar mass of compound is _______ \mathrm{gmol}^{-1} (Nearest integer).

Option: 1

200


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

Let \mathrm{M} is the molar mass of the compound (\mathrm{g} / \mathrm{mol})

mass of compound=0.01 \mathrm{M} gm

mass of carbon =0.01 \mathrm{M} \times \frac{60}{100} 

mass of carbon=\frac{0.01 \mathrm{M}}{12} \times \frac{60}{100}

moles of \mathrm{CO}_2 from combustion =\frac{4.4}{44}= moles of carbon
$$ \begin{aligned} & \frac{0.01 \mathrm{M}}{12} \times \frac{60}{100}=\frac{4.4}{44} \\ & \mathrm{M}=\frac{4.4}{44} \times \frac{100}{60} \times \frac{12}{0.01}=200 \mathrm{gm} / \mathrm{mol} \end{aligned}

Posted by

Ritika Harsh

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