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When 5 moles of He gas expand isothermally and reversibly at 300 K from 10 liter to 20 liter, the magnitude of the maximum work obtained is ___________J. [ nearest integer] 

	ext { (Given : } mathrm{R}=8.3 mathrm{~J} mathrm{~K}^{-1} mathrm{~mol}^{-1} 	ext { and } log 2=0.3010 	ext { ) }

Option: 1

8630


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

Given,
\begin{aligned} &\text{n=5} \\ &\text{T=300} \mathrm{~K} \\ &\mathrm{V_{1}=10} \\ &\mathrm{V_{2}=20} \end{aligned}

Isothermal work \mathrm{=-n R T \ln \left(\frac{V_{2}}{V_{1}}\right)}
                        \begin{aligned} &=-5 \times 8.3 \times 300 \times \ln 2 \\ &=-5 \times 8.3 \times 300 \times 2.303 \times 0.3010 \\ &=-8630.37 \end{aligned}

Thus, magnitude of work is 8630 J when rounded off to the nearest integer.

Answer is 8630

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