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When 5.82 ampere Current was passed for 1.0 hour into nitrobenzene in acidic medium; the amount of p-aminophenol produced is

Option: 1

1.98


Option: 2

2.87


Option: 3

3.44


Option: 4

5.91


Answers (1)

best_answer

4 e^{-}+4 \mathrm{H}^{+}+\mathrm{C}_6 \mathrm{H}_5 \mathrm{NO}_2 \longrightarrow \mathrm{C}_6 \mathrm{H}_4(\mathrm{OH})\left(\mathrm{NH}_2\right)+\mathrm{H}_2 \mathrm{O}
\mathrm{V_ \mathrm{f}=4 \quad \omega= zIt=\frac{E}{F} \times I \times t \quad\left(E=\frac{M}{4}\right) }
\mathrm{ \omega=\frac{109 \times 5.82 \times 60 \times 60}{4 \times 96500} \\ }

\mathrm{ \omega=5.91 }.

Posted by

himanshu.meshram

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