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When a certain metallic surface is illuminated with monochromatic light of wavelength \lambda, the stopping potential for photoelectric current is 3 \mathrm{~V}_0.When the same surface is illuminated with light of wavelength 2 \lambda, the stopping potential is \mathrm{V}_0.The threshold wavelength for this surface for photoelectric effect is

 

Option: 1

6 \lambda
 


Option: 2

4 \lambda / 3
 


Option: 3

4 \lambda
 


Option: 4

8 \lambda


Answers (1)

best_answer

\mathrm{hv}=\mathrm{W}_0+\mathrm{eV}

\text { Here, } \frac{\mathrm{hc}}{\lambda}=\frac{\mathrm{hc}}{\lambda_0}+\mathrm{e}\left(3 \mathrm{~V}_0\right)

\text { and } \frac{\mathrm{hc}}{2 \lambda}=\frac{\mathrm{hc}}{\lambda_0}+\mathrm{eV}_0

Solving we get \lambda_0=4 \lambda

 

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Gaurav

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