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When a container have 16 g of Helium and 96 g oxygen at standard temperature and pressure find the volume of container in \mathrm{\left(m^3\right)}.

 

Option: 1

1.56 \times 10^{-1}


Option: 2

1.56 \times 10^{-3}


Option: 3

1.56


Option: 4

1.56 \times 10^{-5}


Answers (1)

best_answer

\mathrm{(\text { mole })_{\text {Total }}=\eta_{\text {He }}+\eta_{\text {oxygen }}}

                             \begin{aligned} \\& =\frac{16}{4}+\frac{96}{32} \\ \\& =4+3 \\ \\& =7 \end{aligned}

At STP, 1 mole occupy 22.4 litre

So 7 mole occupy = (22.4\times7) litre

                              =156.8 litre

                               =156.8 \times 10^{-3}\mathrm{m^{3}}

Posted by

Rishi

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