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When a harmonic wave is propagation through a medium, the displacement y of particle of the represented by $y = 5\sin \left ( \frac{2}{\pi}(900t-x) \right )$ . The time period will be:
Option: 1
$\frac{1}{360}s$

Option: 2
$\frac{1}{180}s$

Option: 3
18 s

Option: 4
36s

Answers (1)

best_answer

Comparing the equation with $y=A\sin (\omega t - x)$

$\omega = \frac{2\pi}{T}=\frac{2\pi\times 900}{5}$

$T= \frac{1}{180}s$

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vishal kumar

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