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When a particle executes Simple Hormonic Motion, the nature of graph of velocity as a function of displacement will be :

Option: 1

Circular
 


Option: 2

Elliptical
 


Option: 3

Sinusoidal
 


Option: 4

Straight line


Answers (1)

best_answer

We know that,

\mathrm{V^2=\omega^2\left(A^2-x^2\right) }

\mathrm{\frac{V^2}{\omega^2 A^2}+\frac{x^2}{A^2}=1 }

The nature of graph of velocity as a function of displacement will be elliptical
Hence (2) is correct option

Posted by

HARSH KANKARIA

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