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When current in a coil changes from 5 A to 2 A in 0.1 s, an average voltage of 50 V is produced. The self - inductance of the coil is :

Option: 1

0.67 H


Option: 2

1.67 H


Option: 3

3 H


Option: 4

6 H


Answers (1)

best_answer

According to Faraday’s law of electromagnetic induction,

\varepsilon =L\frac{di}{dt} => 50 = L\frac{(5-2)}{0.1}

L = 5/3 = 1.674

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shivangi.shekhar

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