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When one of the slits of Young's experiment is covered with a transparent sheet of thickness 4.8 \mathrm{~mm}, the central fringe shifts to a position originally occupied by the \mathrm{30^{\text {th }}} bright fringe. What should be the thickness of the sheet if the central fringe has to shift to the position occupied by \mathrm{ 20^{\text {th }}} bright fringe

Option: 1

3.8 mm


Option: 2

1.6 mm


Option: 3

7.6 mm


Option: 4

3.2 mm


Answers (1)

best_answer

If shift is equivalent to n fringes then

\mathrm{ \begin{aligned} & \mathrm{n}=\frac{(\mu-1) \mathrm{t}}{\lambda} \Rightarrow \mathrm{n} \propto \mathrm{t} \Rightarrow \frac{\mathrm{t}_2}{\mathrm{t}_1}=\frac{\mathrm{n}_2}{\mathrm{n}_1} \Rightarrow \mathrm{t}_2=\frac{\mathrm{n}_2}{\mathrm{n}_1} \times \mathrm{t} \\ & \mathrm{t}_2=\frac{20}{30} \times 4.8=3.2 \mathrm{~mm} . \end{aligned} }

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seema garhwal

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