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When plate voltage in diode valve is increased from \mathrm{100 volt} to \mathrm{150 volt} then plate current increases from 7.5 \mathrm{~mA} to 12 \mathrm{~mA}. The dynamic plate resistance will be

Option: 1

10 \mathrm{k} \Omega


Option: 2

11 \mathrm{k} \Omega


Option: 3

15 \mathrm{k} \Omega


Option: 4

11.1 \mathrm{k} \Omega


Answers (1)

best_answer

\mathrm{r_p=\frac{\Delta V_p}{\Delta i_p}=\frac{150-100}{(12-7.5) \times 10^{-3}}=\frac{50}{4.5} \times 10^3=11.1 \mathrm{k} \Omega }

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Anam Khan

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