Get Answers to all your Questions

header-bg qa

when the string of a sonometer of length \mathrm{L} between the bridges vibrates in the second overtone, the amplitude of vibration is maximum at -
 

Option: 1

\mathrm{\frac{L}{2}}

 


Option: 2

\mathrm{\frac{L}{4} and \frac{3 L}{4}}


Option: 3

\mathrm{\frac{L}{6} \: and \: \frac{3 L}{6}}


Option: 4

\mathrm{\frac{L}{8}, \frac{3 L}{8} and \frac{52}{6}}


Answers (1)

best_answer

\mathrm{\therefore \quad 3 \frac{\lambda}{2} =L }

\mathrm{\lambda =\frac{2 L}{3}}

Antinodes will be obtained at \mathrm{\frac{\lambda}{4}, \frac{3 \lambda}{4}, \frac{5 \lambda}{4}} or

                                            \mathrm{\frac{2}{6}, \frac{3 L}{6} and \frac{5 L}{6}}

Hence option 4 is correct.

Posted by

Rakesh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE